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3 years ago

Which two structures would provide a positive identification of an animal cell under a microscope?

Chemistry

2 answers:

GalinKa [24]3 years ago

8 0

Answer:

C.flagellum, lysosome

Explanation:

Flagellum and lysosome are the most appropriate structures for providing positive identification of an animal cell under a microscope.

Flagellum are thin filaments, formed by microtubules in their central portion, that allow the cell to swim by liquid means. Usually a flagellate cell has only one flagellum, which can average 200 µm in length and 0.2 µm in diameter. Flagellum are structures located in some specific cell types, which would help to identify a cell.

Lysosomes are organelles present in the cytoplasm of the vast majority of eukaryotic cells, which facilitates their identification. Inside the lysosomes we can find a lot of digestive enzymes.

lisabon 2012 [21]3 years ago

7 0

I would say C.flagellum,lysosome because I took the test tell me if wrong!

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Balance these equations! 1) AIBr; + K- KBr + AI

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Answer:

Instructions on balancing chemical equations:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

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To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.

Example: Fe{3+} + I{-} = Fe{2+} + I2

Substitute immutable groups in chemical compounds to avoid ambiguity.

For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,

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Compound states [like (s) (aq) or (g)] are not required.

If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.

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Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reage

Explanation:

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2 years ago

A student receives 83.2 points, 44.6 points, 74.4 points, and 52.3 points on each of four tests. Determine the student’s test av

Leya [2.2K]

Answer:

Average = 63.6

Explanation:

Average : The average of the given set of points can be calculated by dividing sum of the total point to the number of points.

$Average =\frac{Sum\ of\ points}{Number\ of\ points}$

The points that are given in this equation are:

83.2 , 44.6 , 74.4 , 52.3 .

These are 4 in number . So average is

$Average =\frac{Sum\ of\ points}{Number\ of\ points}$

$Average =\frac{83.2+44.6+74.4+52.3}{4}$

$Average =\frac{254.5}{4}$

$Average =63.625$

Significant digits : It is the number of digits that carry meaningful value to a measurement. The rules for counting number of significant digits are:

1. all non-zero digit are significant

2.Any zero between two non-zero are also significant.(305 = 3 significant digit )

3. Zero before the decimal are non-significant (0.003 = only 1 significant digit)

Zero after decimal are significant (3.00 has 3 significant digit)

4.Zero after non - zero digit is non significant (300 has 1 significant digit).

Significant digits in division :

The answer should have the significant digits that are least in any of number(83.2 , 44.6 , 74.4 , 52.3 )

All have = 3 significant digits.

So least numner of significant digit =3

Answer should have total = 3 significant digits

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Average = 63.6