Answer:
1) 2-bromobutane
2) 1-bromobutane
Explanation:
In the HBr reaction, we will have a <u>markovniknov reaction</u> due to the <u>carbocation formation</u>. The Br- then would be added in the <u>most substituted</u> carbon of the double bond.
In the HBr/peroxide reaction we have the opposite case: an <u>anti-markovnikov reaction</u>. Therefore the Br- would be added in the <u>least substitued</u> carbon of the double bond.
As you get higher the atmospheric pressure lowers. The pressure in the packet of crisps has the pressure at which it has been closed (pressure at the surface of the earth). This means that the air molecules in the packet press harder outside than the air molecules in the atmosphere press on the packet.
O B. The total mass of the reactants equals the total mass of the
products.
Answer:
C₁₀H₁₆O
Explanation:
Molecular formula can be determined from parent peak by using rule of thirteen.
Rule of Thirteen:
First divide the parent peak value by 13 as,
= 152 ÷ 13
= 11.69
Now, multiply 13 by 11,
= 13 × 11 (here, 11 specifies number of carbon atoms)
= 143
Now subtract 143 from 152,
= 152 - 143
= 9
Add 9 into 11,
= 9 + 11
= 20 (hydrogen atoms)
So, the rough formula we have is,
C₁₁H₂₀
Now, add one Oxygen atom to above formula and subtract one Carbon and 4 Hydrogen atoms as these numbers are equal to atomic mass of Oxygen atom as,
C₁₁H₂₀ -------O--------> C₁₀H₁₆O
Calculate Hydrogen deficiency index as,
HDI = (2x + 2 - y) / 2
where,
x = C atoms
y = H atoms
HDI = [2(10) + 2 - 16] / 2
HDI = (20 + 2 - 16) / 2
HDI = (22-16) / 2
HDI = 6 / 2
HDI = 3
It means, Camphor contains 1 double bond and two rings. As, HDI of double bond is 1 and HDI of one ring is 1.