Answer:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
∵AB＝CB
∴∠BAC＝∠BCA
∵AB bisect ∠MAT
∴∠MAB＝∠TAB
Hope my answer helped u :)
Part A:
23 + 13x ≤ 81
Part B:
23 + 13x ≤ 81
<u>-23 </u> <u>-23</u>
13x ≤ 58
<u>/13 </u> <u>/13</u>
x ≤ 4.46
Part C:
This means that you can have 4 cheeseburgers while keeping the fat under 81 grams.
Answer:
X=75 y=90
Step-by-step explanation:
180-105=75
X=75
180-90=90
Y=90
