What are 3(or less) conclusions that you can make based on this histogram?

Mathematics

1 answer:

jeyben [28]2 years ago

7 0

Answer:

1. theres way more younger people compared to older

2. theres a total of approximately 32 people ages 10-14

3. theres a total of approximately 31 people ages 14-19

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Lacey picks blueberries and raspberries from her garden. She has ⅕ as many pounds of blueberries as raspberries. If she picks 1⅘

Mrac [35]

Answer:

2 1/4 pounds of blueberries

Step-by-step explanation:

Blueberries - b, raspberries - x

<u>Equations as per question:</u>

b = x * 1/5
b + 1 4/5 = x

<u>Eliminate b and solve for x:</u>

1/5x = x - 1 4/5
x - 1/5x = 1 4/5
4/5x = 9/5
x = 9/5 : 4/5
x = 9/5 *5/4
x = 9/4
x = 2 1/4

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2 years ago

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The airplane Li's family will be flying on can seat up to 149 passengers. If 96 passengers are currently on the plane,

Flauer [41]

Answer:

A) 96 + x ≤ 149

Step-by-step explanation:

The airplane can hold 149 passengers.

There are already 96 passengers on board.

They can add x additional passengers, as long as they bring the total to no more than 149.

The inequality is

96 + x ≤ 149

3 0

3 years ago

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Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$