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3 years ago

The experimental probability of a coin landing on heads is 7/12. If the coin landed on tails 30 times, find the number of tosses

1 answer:

4 0

Answer: 72 tosses

Explanation: If the probability of landing heads is 7/12, the probability of landing tails is 5/12. So then you do cross multiplication, where you multiply the 12 and the 30, equalling 360. Then divide that by 5, equalling 72.

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8.) What is the product of (x+8) and (x - 5) ?

ki77a [65]

(x + 8)(x - 5)

= x (x - 5) + 8(x - 5)

= x² - 5x + 8x - 40

= x² + 3x - 40 (a)

4 0

3 years ago

Read 2 more answers

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

Prove that the value of the expression 7^8–7^7 +7^6 is divisible by 43.

murzikaleks [220]

Step-by-step explanation:

1. if to evaluate the given experssion, then

7⁶(7²-7+1)=7⁶*43.

2. if to divide this evaluated expression by 43, then

7⁶*43/43=7⁶.

5 0

3 years ago

Help me plsssssssszzzzzzzzzzzzzzzzz

katen-ka-za [31]

Answer:

750 < p < 1500

Step-by-step explanation:

The total cost of the affair for p attendees is ...

750 +2.25p

The average cost is that number divided by p. The answer choices suggest that "between" means that the cost per person cannot be 2.75 or 3.25. Applying the limits to the average cost, we get ...

2.75 < (750 +2.25p)/p < 3.25

2.75 < 750/p + 2.25 < 3.25 . . . . . . . . separating the fraction parts

0.50 < 750/p < 1.00 . . . . . . . . . . . . . . subtract 2.25

2 > p/750 > 1 . . . . . . . . . . . . . . . . . . . . . take the reciprocal*

1500 > p > 750 . . . . . . . . matches choice 4

_____

* Taking the reciprocals of numbers with the same sign reverses their order:

2 < 3 but 1/2 > 1/3

An alternate approach to the solution would be to multiply by p:

0.50p < 750 < 1.00p

To solve this requires it be made into two inequalities:

0.50p < 750 ⇒ p < 1500

and

750 < 1.00p ⇒ 750 < p

Then these would need to be recombined to form the answer:

750 < p < 1500

8 0

2 years ago

Could 1.5, 2.5, 3.5 and 6, 10, 12 be the corresponding sides of two similar triangles

boyakko [2]

Answer:

Step-by-step explanation:

If the ratios of the corresponding sides are equal then they would be the sides of 2 similar triangles.

Calculate the ratio of corresponding sides.

$\frac{6}{1.5}$ = 4

$\frac{10}{2.5}$ = 4

$\frac{12}{3.5}$ ≠ 4

Thus the sides are not the corresponding sides of similar triangles.

4 0

2 years ago