Question

(1 point) A random sample of 1600 home owners in a particular city found 736 home owners who had a swimming pool in their backyard. Find a 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard. Express your results to the nearest hundredth of a percent.

Answer 1

Answer:

Answer: (0.4356,0.4844)

Step-by-step explanation:

Use Ti 84

use function "1-PropZInt".

Enter x = 736

         n = 1600

         c= 0.95

Answer: (0.4356,0.4844)