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Alexxx [7]
3 years ago
9

Baldo is paid $80 per day at his job, plus $15 per hour for every hour (h) that he works overtime. One day, his total earnings w

ere $140. Which equation models this problem?
80 + 15h = 140
140 + 15h = 80
80 + 15 + h = 140
15 + 80h = 140
Mathematics
2 answers:
kkurt [141]3 years ago
3 0
80 + 15h =140 i hope this helped 

Leona [35]3 years ago
3 0
80x + 15x = 140, not sure, what are the options? 
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GrogVix [38]

9514 1404 393

Answer:

  (d)   f(x) = 2x^2 - 16x + 35

Step-by-step explanation:

The x-coordinate of the extreme will be found at ...

  x = -b/(2a)

where the function is f(x) = ax²+bx+c.

The extreme will be a minimum when a > 0. (eliminates choices A and B)

The x-coordinates of the extremes are ...

  C: -(-4)/(2(4)) = 1/2

  D: -(-16)/(2(2)) = 4 . . . . . matches the requirement

The appropriate choice is ...

  f(x) = 2x^2 - 16x + 35

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3 years ago
Plz help me with this!
nikdorinn [45]
B is the answer because 12 divided by 6 is 2 and 18 divided by 6 is 3

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6.106x10^7 in standard form
Aleksandr-060686 [28]
Start with 6.106. move the decimal over 7 spots to the right.
Your answer will be 61,060,000.
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Triangle angle- sum theorem <br>help!!!<br>​
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Answer:

222555413`125431534

Step-by-step explanation:

8 0
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Read 2 more answers
34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
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