The dimensions of the paper are 9 by 5 inches
<h3>How to determine the dimensions?</h3>
Let x represent the length and y, the width
The given parameters are:
Perimeter, P = 28
Area, A = 45
So, we have
P = 2(x + y) = 28
A = xy = 45
Rewrite as:
2(x + y) = 28
xy = 45
By trial by error, we have:
x = 9 and y = 5
This can be proved as follows:
2(9 + 5) = 28--- true
9 * 5 = 45 --- true
Hence, the dimensions of the paper are 9 by 5 inches
Read more about perimeter and area at:
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Answer:
P=7
Step-by-step explanation:
7-3=4
4/2=2
therefore,
p=7
Answer:
Step-by-step explanation:
answer is 2 because cosec^2 theta-cot^ theta is 1and when u multiply 1 and 2 answer is 2
Let "a", "b" and "с" be sides of the triangle ("с" is the longest side). The triangle will be:
right if a² + b² = c²
аcute if a² + b² > c²
obtuse if a² + b² < c²
We have a=2, b=√11 and c=√15
2² + (√11)² = 4 + 11 = 15
and
(√15)² = 15
15 = 15 ⇒ right triangle.
Hope this helps.
Equation:d=3(r)+120
If r equals 62, then the r in d=3r+120 would also be 62.
3(r)+120 --> 3(62)+120
186+120
306
d=306