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3 years ago

PLEASE HELP I ONLY NEED THIS TO GET A 100 IN HOMEWORK!!! HELP PLEASE!

Mathematics

1 answer:

DerKrebs [107]3 years ago

7 0

Answer:

Step-by-step explanation:

First fraction:

Numerator:

(17/40 + 0.6 - 0.005) = 1.02

1⅕ = 1.2

(1.2 ÷ 1.02)×1.7 = 2

Denominator:

5/6 + 4/3 - 53/30

Lcm: 30

(5×5 + 4×10 - 53)/30

12/30 = 0.4

Fraction value: 2/0.4 = 5

Second fraction:

4.75 + 7.5 = 12.25

33 ÷ 33/7

33 × 7/33 = 7

12.25/7 = 1.75

1.75 ÷ 0.25 = 7

Final answer:

5 + 7 = 12

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What is the place value relationship of the 9's in 299

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Ones and tens thats the anwers

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4 years ago

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A scuba diver is at an elevation of −38feet. The diver starts moving at a rate of −12 feet per minute. Identify an inequality th

solniwko [45]

Answer:

x = 13 1/2 or 13.5

Step-by-step explanation:

Flip Equation

-38 - 12x = -200

-12x -38 = -200

Add 38 to both sides

-12x -38 + 38 = -200 + 38

-12x = -162

Divide

-12x/-12 = -162/-12

x = 27/2

Simplify

27/2 = 13 1/2

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7 0

3 years ago

Exercise 12.1.2: The probability of an event under the uniform distribution - random permutations. About A class with n kids lin

Nataly [62]

Answer:

a) $P_a=\frac{1}{n}$

b) $P_b=\frac{1}{n(1-n)}$

c) $P_c=\frac{2}{n}$

Step-by-step explanation:

The question is incomplete:

<em>(a) What is the probability that Celia is first in line? (b) What is the probability that Celia is first in line and Felicity is last in line? (c) What is the probability that Celia and Felicity are next to each other in the line?</em>

a) The probability that Celia is first in line, if there are n kids and all of them have the same chance, is 1/n.

$P_a=\frac{1}{n}$

b) The probability that Celia is first in line and Felicity is last in line is

$P_b=\frac{1}{n} \frac{1}{n-1} =\frac{1}{n(1-n)}$ .

It is deducted like that:

If Celia is placed in the first line (what has a probablity of 1/n), there are left (n-1) kids. Then, the probability of placing Felicity in the last place is 1/(n-1).

Both probabilities multiplied give 1/(n*(n-1)).

c) The probability that Celia and Felicity are next to each other in the line is

$P_c=\frac{2(n-1)!}{n!}=\frac{2}{n}$

There are n! combinations for kids lines, where (n-1)! permutations have Celia before Felicity and other (n-1)! permutations have Felicity before Celia.

Then, we have 2(n-1)! permutations that have Celia and Felicity next to each other, over n! permutations possible.

5 0

3 years ago

EASY TRIG - 15 POINTS

poizon [28]

Answer: The answers are (a) 40 cm and (b) $\sin^{-1}\dfrac{23}{62}.$

Step-by-step explanation: The calculations are as follows:

(a) See the figure (a). As given in the question, A circle with centre 'O' circumscribes a triangle ABC with BC = 20 cm and ∠BAC = 30°. We need to find the diameter DC of the circle.

Let us draw BD. Now, ∠BAC and ∠BDC are angles on the same arc BC, so we have

∠BAC = ∠BDC = 30°.

Also, ∠CBD = 90°, since it stands on the diameter DC. So, ΔBCD will be a right angled triangle.

We can write

$\sin \angle BDC=\dfrac{BC}{DC}\\\\\\ \Rightarrow \sin 30^\circ=\dfrac{20}{DC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{20}{DC}\\\\\\\Rightarrow DC=40.$

Thus, the diameter of the circle = 40 cm.

(b) See the figure (b).

As given in the question, A circle with centre 'O'' circumscribes a triangle DEF with EF = 4.6 inches and diameter GF = 12.4 in.. We need to find the angle EDF.

Let us draw GE. Now, ∠EGF and ∠EDF are angles on the same arc EF, so we have

∠EGF = ∠EDF = ?

Also, ∠GEF = 90°, since it stands on the diameter GF. So, ΔGEF will be a right angled triangle.

We can write

$\sin \angle EGF=\dfrac{EF}{GF}\\\\\\ \Rightarrow \sin \angle EGF=\dfrac{4.6}{12.4}\\\\\\\Rightarrow \sin \angle EGF=\dfrac{23}{62}\\\\\\\Rightarrow \angle EGF=\sin^{-1}\dfrac{23}{62}.$

Thus,

$\angle EDF=\angle EGF=\sin^{-1}\dfrac{23}{62}.$

4 0

3 years ago

PLEASE HeLP ME!!!! IM TIMED

ankoles [38]

Answer:

4 units to the left

Step-by-step explanation:

4 0

3 years ago