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vladimir1956 [14]
3 years ago
6

Please help! Thanks!

Mathematics
2 answers:
kherson [118]3 years ago
6 0

Answer:

3,800

Step-by-step explanation:

Here's how I believe I got the answer

Since the whole area is 7,600 cm2

I think that is saying that you divide in half, since that's the area. Your probably going to think about the perimeter, which divided by two, you get 3,800

My bad if I'm wrong!

Natalka [10]3 years ago
5 0

Answer:

3,800

Step-by-step explanation:

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Please help with sum plz​
belka [17]

The angle is the same

all triangles equal to 180 degrees, so logically, the other angle is 60

It is an equilateral triangle.

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Dey are the same exact triangle

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2 years ago
According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
Please answer the question. The picture is right below.
zhenek [66]
Hey man I’ve never seen nothing like this but I’d you’re doing math on ap classroom , man , GOOD LUCK
5 0
3 years ago
Write 500m out of 4km as a percentage​
xz_007 [3.2K]

Answer:

∴ 5.5% is 55 m of 1 km.

___________________

6 0
3 years ago
How to do the problem I don't get it
DaniilM [7]
5 days * $125 daily fee + $??.?? Deposit = $700

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 625+x=700
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$75 Deposit

I'm not sure what "the rate of change" is

sorry but i hope i helped


ΩΩΩΩΩΩΩΩΩΩ

5 0
3 years ago
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