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pashok25 [27]
3 years ago
11

8. How many 1/3 pound hamburger patties can be made out of 9 pounds

Mathematics
2 answers:
Sedbober [7]3 years ago
8 0

Answer:

27 or im dumb

Step-by-step explanation:

andriy [413]3 years ago
4 0

Answer:

27

Step-by-step explanation:

each pound can make 3 burgers, so 3 x 9 is 27

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A principal of $4,570 is placed in an account that earns 4.5% interest. If the interest is compounded annually, how much money w
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$5695.05

Step-by-step explanation:

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Quadrilateral QRST, with vertices Q (1, 2), R (3, 4), S (5, 6), and T (2, 7), is dilated by a factor of 2 with the center of dil
bija089 [108]

Answer:

Step-by-step explanation:

Given

Quadrilateral QRST

Q (1, 2), R (3, 4), S (5, 6), and T (2, 7)

Dlated Factor = 2

Required

Coordinates of quadrilateral Q′R′S′T′

<em>Provided that a quadrilateral is dilated with the center of dilation at the origin; the new dilated shape is simply the multiplication of the dilation factor by the coordinates of the original shape;</em>

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In other words,

Q'R'S'T' = Dilation factor * QRST

When Q = (1,2)

Q' = 2 * (1,2)

Q' = (2,4)

When R = (3,4)

R' = 2 * (3,4)

R' = (6,8)

When S = (5,6)

S' = 2* (5,6)

S' = (10,12)

When T= (2,7)

T'  = 2 * (2,7)

T' = (4,14)

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3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
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Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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In which

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The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

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