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sdas [7]
3 years ago
9

Multiply.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

D) 2x² + 4x - 30

Step-by-step explanation:

Follow the FOIL method:

FOIL =

First

Outside

Inside

Last

...and is the order you multiply to solve:

(x + 5)(2x - 6) =

(x)(2x) = 2x²

(x)(-6) = -6x

(5)(2x) = 10x

(5)(-6) = -30

Combine like terms. Simplify:

2x² -6x + 10x - 30 = 2x² (-6x + 10x) - 30 = 2x² + 4x - 30

2x² + 4x - 30 is your answer.

~

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The Flynns' monthly budget allowed them to spend 5555 for household expenses. During June and July they
cricket20 [7]

Answer:

They have over spent $925

Step-by-step explanation:

Given:

The Monthly amount Flynn's spent on Household  = $555

Amount spent In June and July together = #2035

To Find:

The over spent amount in June and July = ?

Solution:

For a month the budget is $555

According to the budget the amount they should have spent for the month of June and July will be

=> $555 for June  + $555 for July

=> $1110

But they have spent $ 2035 for June and July together

Si the extra amount will be

Amount spent - actual budget amount

=> $2035 - $1110

=> $925

3 0
3 years ago
From point a travel 12 km south and 10 km west then travel 5 km north how far r u from point a
maks197457 [2]

Answer:17

Step-by-step explanation:

8 0
3 years ago
Last year 40 people adopted a mantee through Fia's foundation. This year 30% more people adopted a manatee . How many people ado
Charra [1.4K]

Number of people adopted a mantee through Fia's foundation = 40

30% more are people adopted a manatee

Number of people adopted = 30% of 40 = (0.30)(40) = 12

People adopted a manatee this year = number of people + 30% of 40

People adopted a manatee this year = 40 + 12

People adopted a manatee this year = 52


3 0
3 years ago
Read 2 more answers
Which of these is an example of an overdraft?
shutvik [7]
The correct answer is "Having $517.98 in you checking account and writing a check for $563.28" because you are spending more money than you have in your account.

Hope this helped :)
5 0
3 years ago
Rad 18x^5y + Rad 32xy^3 - Rad 128xy
True [87]
Sqrt(18x^5y) + sqrt(32xy^3) - sqrt(128xy)
You may separate the roots to produce solvable square roots!

sqrt(9x^4)*sqrt(2xy) + sqrt(16y^2)*sqrt(2xy) - sqrt(64)*sqrt(2xy)

Simplifying makes it ...
(3x^2 + 4y - 8)*sqrt(2xy)
This should be the closest you can get to a simplified equation.
5 0
3 years ago
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