Answer:
1/25
Step-by-step explanation:
The bag has:
- 2 yellow marbles
- 3 red marbles
- 5 blue marbles
- 10 total marbles
The probability of picking a yellow marble is 2/10=1/5.
So, the answer is (1/5)² = 1/25
The range of any graph are the set of all the y-values of the graph. For this graph, it goes all the way from 0 to about 3.5. I'd say the range of this graph was {0, 3.5}. Hope I could help!
We are given that
number of male kittens =7
number of female kittens =5
total number of kittens = number of male kittens + number of female kittens
total number of kittens = 7+5
total number of kittens = 12
now, we can find probability of selecting female kittens
P(female kittens)=(number of female kittens)/( total number of kittens)
P(female kittens) is

now, we are given that
Donna randomly selects one, puts it back, and then randomly selects another
so, both probability are independent
so,
the probability that both selections were female kittens is
=P(female kittens)*P(female kittens)
now, we can plug values
the probability that both selections were female kittens is

...............Answer
The answer is B.
You can't multiply, divide, or subtract because it says find the sum.
Answer:
A) 21/7, or 3
B) 36/5, or 7 1/5
C) 35/25, or 1 15/25, or 1 3/5
D) 54/12, or 4 6/12, or 4 1/2
Step-by-step explanation:
8/7 plus 13/7. You add the numerators (the numbers on top) together. That makes 21. The denominator (the numbers on bottom) stays the same. So it would be 21/7. 7 fits into 21, 3 times.
8/7 más 13/7. Agrega los numeradores (los números en la parte superior) juntos. Eso hace 21. El denominador (los números en la parte inferior) permanece igual. Entonces sería 21/7. 7 encaja en 21, 3 veces.
8/7 plus 13/7. Vous ajoutez les numérateurs (les chiffres du haut) ensemble. Cela fait 21. Le dénominateur (les chiffres du bas) reste le même. Donc, ce serait 21/7. 7 correspond à 21, 3 fois.
8/7 plus 13/7. Quarum numeratores addere (supra de numero) una. 21. Quod facit denominator est (per numeros in fundo) manebit. Ita esset 21/7. Vicium, in VII XXI, III tempora.