Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
Step-by-step explanation:
(-2a² + s)(5a² - 6s)
= (-2a²)(5a²) + (-2a²)(-6s) + (s)(5a²) + (s)(-6s)
= -10a⁴ + 12a²s + 5a²s - 6s²
= -10a⁴ + 17a²s - 6s². (1st option)
Answer:
The 95% confidence interval for the population mean weight of newborn elephants is between 242.12 pounds and 245.88 pounds.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 244 - 1.88 = 242.12 pounds.
The upper end of the interval is the sample mean added to M. So it is 244 + 1.88 = 245.88 pounds
The 95% confidence interval for the population mean weight of newborn elephants is between 242.12 pounds and 245.88 pounds.
4 • 6 = 24
Each student will receive 24 mini loaves of banana bread.
