43+35=78 the answer is 78
If h(t)=-20+11t and you wish to evaluate h(11):
h(11)=-20+11(11)
h(11)=-20+121
h(11)=101
1 cg = 10^-5 kg
8.25 * 10^2 cg = 8.25 * 10^-3 kg
10^-12 kg = 1 nanogram
8.25 * 10^-3 kg = 8.25 * 10^9 nanograms
Therefore, 8.25 * 10^2 cg = 8.25 * 10^9 nanograms.
Answer:
20+24= 2(10+12) = 4(5+6)
Those are two ways to factor 20+24.
I think this should be the answer!!