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Nookie1986 [14]
3 years ago
15

Please help me with this question #13

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
Your hot as hell jeez
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Order the group of parabolas from widest to narrowest.
Mamont248 [21]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2,\ y=-\dfrac{1}{2}x^2,\ y=\dfrac{3}{2}x^2}

Step-by-step explanation:

The equation of a parabola: y = ax²

The larger the value of |a|, the narrower the parabola.

We have the following coefficients a:

\left|\dfrac{1}{4}\right|=\dfrac{1}{4},\ \left|-\dfrac{1}{2}\right|=\dfrac{1}{2},\ \left|\dfrac{3}{2}\right|=\dfrac{3}{2},

We arrange the coefficients from the smallest to the largest:

\dfrac{1}{4}\

Therefore you have the answer:

y=\dfrac{1}{4}x^2,\ y=-\dfrac{1}{2}x^2,\ y=\dfrac{3}{2}x^2

6 0
2 years ago
Use point-slope form to write the equation of a line that passes through the point
Ymorist [56]

Answer:

y= -2x-22.

Step-by-step explanation:

1) the slope-interception common form is y=s*x+i, where 's' and 'i' are the slope and interception, unknown numbers;

2) if x₁= -3; y₁= -16, and s=-2, then the equation of the required line can be written in the point-interception form y-y₁=s(x-x₁); ⇔ y+16= -2(x+3);

3) the required equation in slope-interception form is:

y+16= -2x-6; ⇒ y= -2x-22.

note, the provided solution is not the only and shortest way.

5 0
2 years ago
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