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mario62 [17]
3 years ago
11

If a= (3/6) and b=(-3/-5) find-3a+4b

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

-3a + 4b

= -3(3/6) + 4(-3/-5)

= -3/2 + 12/5

= 9/10

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Two arcades have different pricing structures. Arcade A costs $5 to enter and $0.60 per game. Arcade B costs $7 to enter and $0.
WARRIOR [948]

Answer:

10 games

Step-by-step explanation:

Let C be cost and x be number of games

Arcade A: C = 5 + 0.6x

Arcade B: C = 7 + 0.4x

for both arcades to be the same price, Both C's must be equal, hence we equate the right side of both equations:

5 + 0.6x = 7 + 0.4x   (subtract 5 fromboth sides)

0.6x = 7 + 0.4x - 5

0.6x = 2 + 0.4x  (subtract 0.4x from both sides)

0.6x - 0.4x = 2

0.2x = 2 (divide both sides by 0.2)

x = 2 / (0.2)

x = 10

7 0
3 years ago
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The french club is selling coupon books for $8.25 each. How many coupon books must be sold to earn $5,940?​
leonid [27]
720 because 5940 divided by 8.25 is 720
4 0
4 years ago
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M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]

Answer:

Step-by-step explanation:

Given

<LON = 77°

<LOM = (9x+44)°

<MON = (6x+3)°

The addition postulate is true for the given angles since tey have a common point O:

<LON = <LOM+<MON

Since we are not told what to find we can as well look for the value of x, <LOM and <MON

Substitute the given parameters and get x

77 = 9x+44+6x+3

77 = 15x+47

77-47 = 15x

30 = 15x

x = 30/15

x = 2

Get <LOM:

<LOM = 9x+44

<LOM = 9(2)+44

<LOM = 18+44

<LOM = 62°

Get <MON:

<MON = 6x+3

<MON = 6(2)+3

<MON = 12+3

<MON = 15°

6 0
4 years ago
The position of an object at time t is given by s(t) = 3 - 4t. Find the instantaneous velocity at t = 8 by finding the derivativ
andre [41]
I hope this helps you

s' (t)=0-4


s' (t)=-4

t=8


s' (8)=-4
4 0
3 years ago
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Renee scores an average of 153 points in a game of bowling, and her points in a game of bowling are normally distributed. Suppos
Lelu [443]

Answer:

\sigma=\frac{175-153}{2}=11

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent points in a game of bowling of a population, and for this case we know the distribution for X is given by:

X \sim N(153,unknown)  

Where \mu=153 and \sigma=?

We know that the value for Renee is X=175 and the z score obteined was Z=2.

Solution to the problem

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{X-\mu}{\sigma}

We are interested on the value of \sigma and we can solv for it:

z \sigma = X-\mu

\sigma=\frac{X-\mu}{z}

And replacing the values we have:

\sigma=\frac{175-153}{2}=11

 

5 0
3 years ago
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