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4 years ago

Which pair of ratios do not form a true proportion? Circle all that apply.

Mathematics

2 answers:

Pani-rosa [81]4 years ago

6 0

Answer: In problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. To find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

Step-by-step explanation:

FromTheMoon [43]4 years ago

3 0

Rewrite each ratio as a fraction and reduce. If the reduced fractions are euqal, it is a proportion.

A. 20/5 = 4; 4/2 = 2; not a proportion

B. 3/4 = 3/4; 12/16 = 3/4; proportion

C. 18/8 = 9/4; 3/2 = 3/2; not a proportion

D. 12/24 = 1/2; 3/4 = 3/4; not a proportion

E. 6/9 = 2/3; 3/2 = 3/2; not a proportion

F. 8/6 = 4/3; 4/3 = 4/3; proportion

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A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If the hei

ratelena [41]

The movement of the ping pong ball follows a exponential progression.

The expression for the k-th bounce is: $\mathbf{T_k = 235 \times (0.75)^k}$
The height after the 6th bounce is 41.82 ft
The total distance after the 12th bounce is 1584.84ft.
There will be 31457280 bacteria after a day and a half.

1. Ping pong ball

The given parameters are:

$\mathbf{a = 235}$ --- the initial height

$\mathbf{r = 75\%}$ --- the common ratio

(a) The expression after bouncing k times

To do this, we make use of

$\mathbf{T_n = a \times r^n}$

So, we have:

$\mathbf{T_n = 235 \times (0.75)^n}$

In this case; k = n.

So, the equation becomes

$\mathbf{T_k = 235 \times (0.75)^k}$

Hence, the expression for the k-th bounce is: $\mathbf{T_k = 235 \times (0.75)^k}$

(b) The height after bouncing 6 times

This means that k = 6.

So, we have:

$\mathbf{T_k = 235 \times (0.75)^k}$

$\mathbf{T_6 = 235 \times (0.75)^6}$

$\mathbf{T_6 = 41.82}$

Hence, the height after the 6th bounce is 41.82 ft

(c) The total distance after the 12th bounce

First, we calculate the total height after the 12th bounce using:

$\mathbf{S_k = \frac{a(1 - r^k)}{1 - r}}$

So, we have:

$\mathbf{S_k = \frac{235 \times (1 - 0.75^{12})}{1 - 0.75}}$

$\mathbf{S_k = \frac{235 \times (0.968)}{0.25}}$

$\mathbf{S_k = 909.92}$

So, the total distance is:

$\mathbf{Distance = 2 \times S_k - a}$

$\mathbf{Distance = 2 \times 909.92 - 235}$

$\mathbf{Distance = 1584.84}$

Hence, the total distance after the 12th bounce is 1584.84ft.

(2) Cell division

The given parameters are:

$\mathbf{r = 2/2hr}$ --- rate

$\mathbf{a = 120}$ --- initial number of cells

$\mathbf{t = 18}$ --- number of 2 hours is a day and a half

So, the number of bacteria is:

$\mathbf{T_t = ar^t}$

This gives

$\mathbf{T_t = 120 \times 2^{18}}$

$\mathbf{T_t = 31457280}$

Hence, there will be 31457280 bacteria after a day and a half.

Read more about exponential functions at:

brainly.com/question/11487261

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3 years ago

Read 2 more answers

What is 2.5 and 2 and 3.5 rounded to the nearest tenth

pashok25 [27]

2.5 rounded to the nearest tenth is: 3
3.5 rounded to the nearest tenth is: 4
2 rounded to the nearest tenth is: 2

7 0

3 years ago

Read 2 more answers

Which of the following satisfies Ž -2 = 12

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

if z is 14 than z-2=12

because 14-2=12

7 0

3 years ago

The speed of a stream is 4km/h. A boat travels 6 km upstream in the time it takes to travel 12 km downstream. What is the speed

Usimov [2.4K]

6 km × 1 hour/(b-4 km) = 12 km × (1 hour/(b+4 km)

6/(b-4) hours = 12/(b+4) hours

6(b+4) = 12(b-4)

6b + 24 = 12b - 48
72 = 6b
b = 12
The boat's speed in still water is 12 km/hour.

4 0

4 years ago

45 points! Please help!

Tju [1.3M]

Answer:

Sequence One

Step-by-step explanation:

S = a₁ / (1 − r) is the infinite sum of a geometric series where |r| < 1.

Sequence One: r = 1/5

Sequence Two: r = 2

Sequence Three: not geometric

Sequence Four: r = -3/2

Only Sequence One has |r| < 1.

5 0

3 years ago

Which pair of ratios do not form a true proportion? Circle all that apply.​

Which pair of ratios do not form a true proportion? Circle all that apply.