Triangle ABD is i<span>nscribed in circle and </span>has hypotenuse as circle's diameter so angle ABD must be 90°
Since it is parallelogram, ∠ABD = ∠BDC = 90° and it is given that ∠ADB = 30°
So we have ∠CDO = ∠CDB + ∠ADB = 30° + 90° = 120°
Final answers: ∠CDO = 120° and ∠ABD = 90°
The vertices of AMNO are M (1,3), N (4,9), and O (7,3). The vertices of APQR are P (3,0), Q (4,2), and R (5,0) Which conclusion
Pavel [41]
Answer:
the correct answer should be C
Step-by-step explanation:
hope this helps you
Answer:
the answer is 93.6
Step-by-step explanation:
<h3>
Answer: b = 17</h3>
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Explanation:
The line must go through the point (5,2) which means x = 5 and y = 2 pair up together.
We'll plug these x and y values into the equation and solve for b.
y = -3x+b
2 = -3(5)+b
2 = -15+b
2+15 = b
17 = b
b = 17
The equation y = -3x+b turns into y = -3x+17
Answer:
Step-by-step explanation:
Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.
<h3>
<u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>
• The sum of n terms of an AP is
![\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Corange%7B%5Csf%20S_n%20%3D%20%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D%20%7D%7D)
• nth term of an AP is given by ,
