Question

What is the sum of the geometric series rounded to the nearest whole number?

Answer 1

Answer:

Option A. $4$

Step-by-step explanation:

we know that

The sum of a geometric series is equal to

$Sum=a(\frac{1-r^{n}}{1-r})$

where

a is the first term

r is the common ratio

n is the number of terms

In this problem we have

$a=2,r=0.5,n=16$

substitute the values

$Sum=2(\frac{1-0.5^{16}}{1-0.5})=4$