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antoniya [11.8K]
4 years ago
9

Solve for x, x^2-3x-5=0

Mathematics
1 answer:
Sophie [7]4 years ago
7 0

Okay so for this one, we have to isolate our X.Lets start by moving the negative 5 on the other side of the equal sign. Remember to not mix a number that is with an X with a normal number (in this case it would be the -3x and the -5). So in putting our -5 on the other sign it becomes positive. Here’s what we have: x^2-3x=5. x^2 is the same thing as 2x.So now you have to minus 3x off of your 2x. This gives us -1x, but can just be put as -x. So now we have -x=5. You’re answer could either be 5 or -5 if you decided to divide it by -1 seeing as your -x is technically -1.

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