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antoniya [11.8K]
3 years ago
9

Solve for x, x^2-3x-5=0

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Okay so for this one, we have to isolate our X.Lets start by moving the negative 5 on the other side of the equal sign. Remember to not mix a number that is with an X with a normal number (in this case it would be the -3x and the -5). So in putting our -5 on the other sign it becomes positive. Here’s what we have: x^2-3x=5. x^2 is the same thing as 2x.So now you have to minus 3x off of your 2x. This gives us -1x, but can just be put as -x. So now we have -x=5. You’re answer could either be 5 or -5 if you decided to divide it by -1 seeing as your -x is technically -1.

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Answer:

y=13(4)^x

Step-by-step explanation:

We have the exponential function of the form:

y=ab^x

And it goes through the points (0, 13) and (3, 832).

Hence, when we substitute in 0 for x, we should get 13 for y. Therefore:

13=ab^0

Since anything to the zeroth power is 1, this yields:

a=13

So, we determined that the value of a is 13.

So, our function is now:

y=13b^x

We will need to determine b. We know that y equals 832 when x is 3. Hence:

832=13(b)^3

Divide both sides by 13:

b^3=64

Take the cube root of both sides:

b=4

Hence, our b value is 4.

Therefore, our entire equation is:

y=13(4)^x

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Step-by-step explanation:

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Read 2 more answers
Graph the data in the table. Which kind of function best models the data? Write an equation to model the data. quadratic; y = 2.
Oksanka [162]

Answer:

Option (1)

Step-by-step explanation:

x               -2              -1                 0                    1                   2

y               10            2.5                0                  2.5                3.0

Ist difference,

d_1=y_2-y_1

    =2.5-10=-7.5

d_2=y_3-y_2

    =0-2.5

    = -2.5

d_3=y_4-y_3

    =2.5-0

    = 2.5

d_4=y_5-y_4

    =10.0-2.5

    = 7.5

2nd difference,

x_1=d_2-d_1

    =-2.5+7.5

    = 5

x_2=d_3-d_2

    =2.5+2.5

    = 5

x_3=d_4-d_3

    =7.5-2.5

    = 5

Since 2nd difference is common, given table represents a quadratic equation.

Let the equation is,

y = ax²+ bx + c

For a point (0, 0) passing through the quadratic equation,

0 = c

Therefore, quadratic equation is y = ax² + bx

Since ordered pair (-1, 2.5) passes through the graph of the function,

2.5 = a(-1)² + b(-1)

a - b = 2.5 ------(1)

For another point (1, 2.5)

2.5 = a(1)² + b(1)

a + b = 2.5 ------(2)

By adding equations (1) and (2),

2a = 5

a = 2.5

and from equation (2)→ y = 0

Therefore, equation of the quadratic function given in the table is y = 2.5x²

Option (1) is the answer.

8 0
3 years ago
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