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podryga [215]
3 years ago
5

What is 60 divided by 3?

Mathematics
2 answers:
Yakvenalex [24]3 years ago
5 0
The answer of 60/3

is

20
Rudik [331]3 years ago
3 0
The answer to this problem is 20

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What is the highest unit price for kazoo
labwork [276]
There needs to be more information in order to solve your problem.


I'm sorry :(

7 0
3 years ago
Write this expression using exponents
alexdok [17]

Answer:

4p^{2} or 4p^2

Step-by-step explanation:

Combine like terms:

4 x 4 and p x p

4^2 and p^2

4p^2

4 0
2 years ago
I really need help I’m very confused
Vaselesa [24]

Answer:

10: -11n^5

12: 6k^2 -6k+7

Step-by-step explanation:

Ok so what your gonna do is add or subtract the ones with the same exponent.

so -15+4= -11 since they are both n^5 you can add them so your answer is:

-11n^2

now you have 8k^2-k-5k+7-2k. so you are gonna rearrange them so the same exponents are together.(keep the sign in front in front, if no sign it is positive)

8k^2-2k^2-5k-k+7

add like exponents

6k^2-6k+7

6 0
3 years ago
In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were re
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μemployed(μ1) be the sample mean of students who are employed and μnot employed(μ2) be the sample mean of students who are not employed

The random variable is μ1 - μ2 = difference in the mean of the employed and unemployed students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(μ1 - μ2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 3.22

μ2 = 3.33

s1 = 0.475

s2 = 0.524

n1 = 172

n2 = 116

t = (3.22 - 3.33)/√(0.475²/172 + 0.524²/116)

t = - 1.81

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.475²/172 + 0.524²/116]²/[(1/172 - 1)(0.475²/172)² + (1/116 - 1)(0.524²/116)²] = 0.00001353363/0.00000005878

df = 230

We would determine the probability value from the t test calculator. It becomes

p value = 0.036

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis.

Therefore, at a 5% significant level, this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed

3 0
3 years ago
A 5-gallon jug of cleaning solution contains 6% bleach. How much pure water should be added to it to dilute to 4% bleach?
mihalych1998 [28]
Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach?  well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.

if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.

the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.

\bf \begin{array}{lcccl}&#10;&\stackrel{gallons}{quantity}&\stackrel{\textit{\% of bleach}}{amount}&\stackrel{\textit{gallons of bleach}}{amount}\\&#10;&------&------&------\\&#10;\textit{pure water}&x&0.00&0x\\&#10;\textit{6\% solution}&5&0.06&0.3\\&#10;-----&------&------&------\\&#10;mixture&y&0.04&0.04y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+5=\boxed{y}\\&#10;0x+0.3=0.04y\\&#10;---------\\&#10;0.3=0.04\left( \boxed{x+5} \right)&#10;\end{cases}&#10;\\\\\\&#10;0.3=0.04x+0.2\implies 0.1=0.04x\implies \cfrac{0.1}{0.04}=x\implies 2.5=x
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3 years ago
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