Answer:
5
Step-by-step explanation:
move the terms
collect like terms
calculate
divide both side

Let's solve ~




It's factorized now ~ And if you want to find the zeros then equate the expression with 0.
And you will get ;
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Given:
CDEF is dilated by a scale factor of
to form the quadrilateral C'D'E'F'.
To find:
The measure of side E'F'.
Solution:
If a figure is dilated by a scale factor of k, then the side of dilated figure is k times of corresponding side of original figure.
CDEF is dilated by a scale factor of
to form the quadrilateral C'D'E'F'. So,

From the given figure it is clear that
. So,


Therefore, the measure of side E'F' is 9 units.
Answer:
Equation of the line:
.
Step-by-step explanation:
Let
and
denote the coordinates of these two points, respectively.
Calculate the slope
of this line:
.
Notice that the slope is zero because the two points have the same
-coordinates (
) even though their
-coordinates are distinct (
.)
Equation for this line in point-slope form:
.
.
Rewrite and simplify to obtain the equation of this line in slope-intercept form:
.
The
-term was eliminated because the slope was zero.
Answer:
60 miles an hour
Step-by-step explanation:
^^^^^^^^