find two numbers such that the sum of twice the first and thrice the second is 92 ,and four times the first exceeds seven times
1 answer:
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Answer:
Three equivalent ratios of are
,
and
.
Step-by-step explanation:
We are given a fraction .
We need to find the three equivalent ratios/fractions of .
The common factor of 14 and 2 is 2.
So, dividing top and bottom by 2, we get
14÷2 = 7 and 2÷2 that is .
Multiplying fraction by a common number 3 in top and bottom, we get
7 × 3 = 21
1 × 3 = 6
So, we get another equivalent fraction .
Multiplying fraction by a common number 3 in top and bottom, we get
7 × 4 = 28
1 × 4 = 4
So, we get another equivalent fraction .
Therefore, three equivalent ratios of are
,
and
.