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nasty-shy [4]
3 years ago
7

How can you simplify (image)?

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0
B.

x^2+2-35 would factor into (x+7)(x-5)

×^2+4-21 would factor into (x+7)(x-3)
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What is 5,000 x 60 x 2
goldenfox [79]
Do it as simply as possible. 5000 × 2 = 10000. 60 × 10000 = 600000. Because multiplying by a factor of 10 is the easiest possible, always try to get a factor of 10 every time.
7 0
3 years ago
Area of a triangle can be found using the formula A = 1/2 bh where B is the base of the triangle and H is the height of the tria
Ostrovityanka [42]

Answer:

The correct option is option 3

Step-by-step explanation:

Monomials are algebraic expressions that contain one term. It can be variables combined together to make one single term. It can be a single variable combined many times. As long as it is one single entity, it is a monomial

Given the formula for the area of the right angles triangle above to be

A =1/2bh

Where

b = 6x = base of the right angle triangle and

h = 7x = height of the right angle triangle.

The area would be

A = 1/2 × 7x × 6x

A= 42x^2 / 2

A= 21x^2 inches^2

Also written as

21x^2 squared inches

21x^2 is a monomial

6 0
3 years ago
Will get 70 points if you help me ​
White raven [17]

Answer:

The x-intercepts of a function are found where the graph of a function crosses the x-axis on a pair of Cartesian coordinate axes. How to Find the X-intercepts of a Function The x-intercepts of a function f (x) is found by finding the values of x which make f (x) = 0. Write f (x) = 0, and solve for x to find the x-intercepts of a function.

Step-by-step explanation:

find the x-intercepts ans you will be able to answer the rest of the question then fill in the blanks

hope this helps :)

7 0
2 years ago
Read 2 more answers
What are the period and phase shift for f(x) = 3 tan(4x + π)?
Y_Kistochka [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now.. with that template above in mind, let's see yours


\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

7 0
3 years ago
4 over x+4 - 2 over x+1
babymother [125]
(4/(x+4-2))/x+1

4/(x+2)=x/4+1/2

(x/4+1/2)/x+1

x=-2/5


7 0
2 years ago
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