Answer:
These lines are perpendicular.
Step-by-step explanation:
Put both equations in the slope intercept form of a line.
y = -6x - 8 This is already in the slope intercept form for a line
-x + 6y = 12 Add x to both sides of the equation
6y = x + 12 Divide through the whole equation by 6
y = 1/6x +2
Now we compare the two slopes of -6 and 1/6. They are negative reciprocals of each other. That means that the line are perpendicular.
Answer:
Point A ends up: <u>Outside of triangle BCD</u>
Now gimmie Brainliest ;)
X = width
2x + x = 3 · 13.73
3x = 41.19
x = 13.73
The width is 13.73 units.
A = 1/4 * (pi) * d^2
A = 1/4 * (pi) * 8^2
A = 1/4 * (pi) * 64
A = 1/4(64) * (pi)
A = 64/4 * (pi)
A = 16 (pi) in^2
Your answer is 16 pi in^2
~Silver
Answer:
Step-by-step explanation:
Given that
Slope m=-3
A point (x, y)=(4,-2)
Equation of a line can generally be written as
y=mx+c
Where, m is the slope
And c is the intercept on y-axis
Since we are given m=-3
Then, y=mx+c becomes
y=-3x+c
To get c, let substitute the point given, i.e x=4 and y=-2
y=-3x+c
-2=-3(4)+c
-2=-12+c
-2+12=c
c=-2+12
c=10
y=mx+c, then m=-3 and c=10
Then, the equation the line becomes y = -3x + 10
This is the required line equation
