A machine that produces ball bearings has initially been set so that the mean diameter of the bearings it produces is 0.500 inch
1 answer:
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Answer:
Step-by-step explanation:
Using the exact values of the given trig functions, then
sin45° × sin30° × cos60°
= ×
×
=
Given:
Length of the cuboid tank = 4 m
Breadth = 2.5 m
Height = 2.4 m
One third of the tank is filled with water.
1 cubic meter = 1000 liters.
To find:
The quantity of the water in the tank.
Solution:
Volume of a cuboid is:
Where, l is length, b is breadth and h is the height.
The volume of the tank is :
Volume of tank is 24 cubic meter.
One third of the tank is filled with water. So, the volume of the water is
The volume of water is 8 cubic meters.
We have,
1 cubic meter = 1000 liters.
8 cubic meter = 8000 liters.
Therefore, the quantity of the water in the tank is 8000 liters.
The water level increases by 0.608 meters per minute when the water is 3.5 m deep
<h3>How to determine the rate?</h3>The given parameters are:
- Radius, r = 3
- Height, h = 7
- Rate in, V' = 4.3m^3/min
The relationship between the radius and height is:
r/h = 3/7
Make r the subject
r = 3h/7
The volume of a cone is;
This gives
Expand
Differentiate
Make h' the subject
When the water level is 3.5.
We have:
Also, we have:
V' = 4.3
So, the equation becomes
Evaluate the products
Evaluate the quotient
h' = 0.608
Hence, the water level increases by 0.608 meters per minute
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