Answer:
The answer would be C < 2
Answer:There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?
Step-by-step explanation
There are 72 heads (chicken and rabbit) and 200 legs. How many chickens and rabbits are present totally?
Legs of a chicken = 2
Legs of a rabbit = 4
Total heads = 72
Total legs= 200
Let's assume that each of them has minimum 2 legs.
So 72*2 = 144 legs
Remaining legs: 200-144= 56
These remaining legs belong to rabbit because rabbit has 4 legs each.
2*Rabbits= 56
Rabbits= 56/2 = 28
Out of 72, 28 are rabbits. So there are 72-28= 44 chicken.
<span> (6y^2 + 4y + 5) – (3 – 7y + y^2)
= </span><span> 6y^2 + 4y + 5 – 3 + 7y - y^2
= 5</span>y^2 + 11y + 2
hope it helps
C2 + a2 +2 = b
Would be the new formula
Answer:
900 large boxes were sold, and 750 small boxes.
Step-by-step explanation:
This question can be solved by a system of equations.
I am going to say that:
x is the number of large boxes of cookies sold.
y is the number of small boxes of cookies sold.
A total of 1,650 boxes of Girl Scout cookies were sold last week.
This means that
So
Each large box cost $3.50 and each small box cost $2.00. The Girl Scout group earned $4,650.
This means that
Since
900 large boxes were sold, and 750 small boxes.
