Pretty sure it’s 4/x-1 if u use synthetic division.
It is given that the diameter of the sphere increases <span>at the rate of 3 inches more than the time, t.
This means that:
at a certain time = t seconds
the diameter of the sphere will be equal to t + 3
Based on this:
at t = 3 seconds
diameter of the sphere = t + 3 = 3 + 3 = 6 inches = </span><span>0.1524 meters
and radius of sphere = 0.5 x </span><span>0.1524 = 0.0762 meters
Volume of the sphere can be calculated using the following rule:
volume of sphere = (4/3) x pi x (radius)^3
Substituting in this equation, we can get the volume of the sphere at t = 3 seconds as follows:
volume at t=3 seconds = (4/3) x 3.14 x (</span>0.0762)^3 = 1.8533 x 10^-3 m^3
We are to answer the questions given the sales and advertisement function
The answers are given below
Given:
S = 9000 + 12A
Where,
S = Monthly sales revenue
A = monthly advertising expenditure
a. If the firm does not spend on advertisement
S = 9000 + 12A
Where,
A = 0
S = 9000 + 12A
S = 9000 + 12(0)
S = $9000
b. If the firm spends $800 on advertising one month
S = 9000 + 12A
= 9000 + 12(800)
= 9000 + 9600
= 18,600
S = $18,600
c. S = 9000 + 12A
When
S = $15,000
15,000 = 9000 + 12A
15000 - 9000 = 12A
6000 = 12A
A = 6000/12
= 500
A = $500
d. If the firm increases monthly expenditure on advertising by $1
If A increases to $501
S = 9000 + 12A
= 9000 + 12(501)
= 9000 + 6,012
= 15,012
S increases to $15,012
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