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Sati [7]
3 years ago
5

The senior class at Snellville rented and filled 12 vans and 14 buses with 796 students. General High rented and filled 14 vans

and 12 buses with 738 students. How many students would fill 2 buses and 3 vans?

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

133 students would fill 2 buses and 3 vans

Step-by-step explanation:

Let x be the no. of students in each van

No. of students in 12 vans = 12x

No. of students in 14 vans = 14x

Let y be the no. of students in each bus

No. of students in 14 buses = 14y

No. of students in 12 buses = 12y

We are given that The senior class at Snellville rented and filled 12 vans and 14 buses with 796 students.

12x+14y=796 ---1

We are also given that General High rented and filled 14 vans and 12 buses with 738 students.

14x+12y=738 ---2

Plot 1 and 2 on graph

12x+14y=796 --- Green line

14x+12y=738 --- Purple line

Intersection point gives the solution

Intersection point=(x,y)=(15,44)

No. of students in 1 van = 15

No. of students in 3 vans = 15 \times 3 = 45

No. of students in 1 bus = 44

No. of students in 2 buses =44 \times 2 = 88

So,Total no. of students in 3 vans and 2 buses = 45+88=133

Hence 133 students would fill 2 buses and 3 vans

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What two numbers have a product of -2 and a sum of 7
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<em>Greetings from Brasil...</em>

According to the statement of the question, we can assemble the following system of equation:

X · Y = - 2      i

X + Y = 7       ii

isolating X from i and replacing in ii:

X · Y = - 2

X = - 2/Y

X + Y = 7

(- 2/Y) + Y = 7     <em>multiplying everything by Y</em>

(- 2Y/Y) + Y·Y = 7·Y

- 2 + Y² = 7X     <em> rearranging everything</em>

Y² - 7X - 2 = 0      <em>2nd degree equation</em>

Δ = b² - 4·a·c

Δ = (- 7)² - 4·1·(- 2)

Δ = 49 + 8

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X = (- b ± √Δ)/2a

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3 years ago
I am stuck on these last four questions please help if possible.
zloy xaker [14]

Answer:

Step-by-step explanation:

9). -2.2(4 - 1.9x) = 3.3(0.2x - 0.8)

    -8.8 + 2.2(1.9x) = 0.66x - 2.64

    -8.8 + 4.18x = 0.66x - 2.64

     4.18x - 0.66x = 8.8 - 2.64

     3.52x = 6.16

     x = 1.75

10). 3.2(1 + 2.6x) = 2.4(x - 3.6)

     3.2 + 8.32x = 2.4x - 8.64

     8.32x - 2.4x = -3.2 - 8.64

     5.92x = -11.84

      x = 2

11). 4.6(2x - 5.5) = 3.9 + 0.8(1 + 5.5x)

     9.2x - 25.3 = 3.9 + 0.8 + 4.4x

     9.2x - 25.3 = 4.7 + 4.4x

     9.2x - 4.4x = 25.3 + 4.7

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12). 0.2(3x + 2.5) - 4.9 = 3.8 - 2.2(x - 5.5)

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     0.6x + 2.2x = 15.90 + 4.4

     2.8x = 20.30

     x = 7.25

4 0
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