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Vinvika [58]
2 years ago
14

Helpppppp meee please

Mathematics
2 answers:
a_sh-v [17]2 years ago
7 0

Answer:

a) $14.45 b) 1.45x+1.2y

Step-by-step explanation:

5*1.45+6*1.2=14.45

Volgvan2 years ago
4 0

Answer:

7.25 and 7.20

Step-by-step explanation:

I calculated and got it correct

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The speed (v) of a gear varies inversely as the number of teeth (t). If a gear that has 48 teeth makes 20 revolutions per minute
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80

Step-by-step explanation:

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2 years ago
What is the midpoint of the line segment with endpoints (1,-6) and (-3,4)?
kirill115 [55]

Answer:

(-1,-1)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

(1+-3)/2 = -2/2 = -1

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

(-6+4)/2 = -2/2 = -1

(-1,-1)

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A biking track has a length of 0.9 miles . How long is this in feet ?
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3 years ago
Read 2 more answers
Question 5 and 6 please help me
sp2606 [1]

Problem 5

The function is continuous for the given domain x \ge 6

This is because y = (-5/6)x+5 is itself continuous, and any interval subset of this function is also continuous. We can plug in any real number that is equal to 6 or larger, and get some y output. If we plugged in x = 6, then we'd get

y = (-5/6)x+5

y = (-5/6)*6 + 5

y = -5+5

y = 0

This is the largest y value possible. Why? Because y = (-5/6)x+5 has a negative slope, so the graph is going downhill as you read it from left to right. As x gets bigger, y gets smaller. The smallest x value allowed in the domain produces the largest y value in the range. There is no smallest y value as the y values keep going down forever.

The range is therefore y \le 0

In interval notation, you can write the range as (-\infty, 0]. The square bracket indicates "include this endpoint as part of the range".

======================================================

Problem 6

The function is discrete for this given domain. The domain itself is a discrete list of values. We cannot plug in values between say 0 and 2. We can only substitute one of those values from the list given. Consequently, the y values will also be a list, and not an interval like problem 5 had.

-----------

If you plugged in x = -4, then you should get...

y = (-1/2)*(-4)+2

y = 2+2

y = 4

So the input x = -4 lead the output y = 4

Repeat for x = -2

y = (-1/2)x+2

y = (-1/2)*(-2)+2

y = 1+2

y = 3

and the same for x = 0 as well

y = (-1/2)x+2

y = (-1/2)*0 + 2

y = 0 + 2

y = 2

and x = 2 also

y = (-1/2)x+2

y = (-1/2)*2 + 2

y = -1+2

y = 1

Finally, plug in x = 4

y = (-1/2)x+2

y = (-1/2)*4+2

y = -2+2

y = 0

---------------

If we plugged each of these x values {-4, -2, 0, 2, 4} one at a time into the equation y = (-1/2)x+2, then we get this list of values {4, 3, 2, 1, 0}

Sorting the values from smallest to largest, we have this range {0, 1, 2, 3, 4}

3 0
2 years ago
4:3 is an example of...
Ghella [55]

Answer:

A ratio

Step-by-step explanation:

A quantitative relation between two amounts showing the number of times one value contains or is contained within the other

7 0
2 years ago
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