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nydimaria [60]
4 years ago
5

Simplify completely quantity x squared plus 4 x minus 5 over quantity 5 x squared minus 8 x plus 3 times quantity 20 x minus 12

over x squared minus 6 x minus 55 how do I simplify this?
Mathematics
1 answer:
NNADVOKAT [17]4 years ago
4 0
The way to do is is to write down expression, find factors of each polynomial and than cancel as many as possible. What remains is our simplified version of starting expression.

We start with this:

\frac{x^2+4x-5}{5x^2 - 8x +3}* \frac{20x-12}{x^2-6x-55}

Now we factor every polynomial

\frac{(x+5)(x-1)}{(5x-3)(x-1)}*  \frac{4(5x-3)}{(x-11)(x+5)}

now we can cancel fallowing factors:
5x-3, x-1 and x+5

after that we left with:
\frac{4}{x-11}
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On the graph below are three points X, Y, and Z. Write the coordinates for the given dilation.
Julli [10]

ANSWER

( -  \frac{3}{2} , - 1)

EXPLANATION

From the graph, the coordinates of Y are:

(3,2)

We want to find the image of this point after a dilation by a scale factor of -½ about the origin.

The rule for the dilation is :

(x,y)\to( - \frac{1}{2}  x, -  \frac{1}{2} y)

To find the coordinates of Y', we plug the coordinates of Y.

Y(3,2)\to \: Y'( - \frac{1}{2}  (3), -  \frac{1}{2}(2) )

Y(3,2)\to \: Y'( - \frac{3}{2}, - 1)

The first choice is correct.

6 0
4 years ago
The length of a rectangle is 12 in and the perimeter is 56 what us the width of the rectangle
Aleks [24]
Hi there!

We can find the perimeter of a rectangle by using the following formula:

perimeter = 2 × width + 2 × length

In the question, we are given the following data: the length of the rectangle is 12 in and the perimeter is 56. Let's substitute this into our formula!

56 = 2 × width + 2 × 12
Multiply first.

56 = 2 × width + 24
Now subtract 24 from both sides.

32 = 2 × width
And finally, to find the width of the rectangle, divide both sides of the equation by 2.

16 = width
(we can eventually switch sides in the equation).

width = 16
~ Hope this helps you!
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Answer:

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Step-by-step explanation:

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Troyanec [42]
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