Assuming we are solving for t
2<-1t
3
There are

ways of pairing up any 2 members from the pool of
contestants. Note that

so that

Quadratic is in the form
ax^2+bx+c=0
so distribute and stuff and simplify
remember
a(b+c)=ab+ac
(x+2)^2+5(x+2)-6=0
remember order of opertaions
(x+2)(x+2)+5(x+2)-6=0
x^2+4x+4+5x+10-6=0
add like terms
x^2+9x+8=0
Yes. You can find that out by multiplying .1 by 274. It equals 27.4.
Answer:
x < 3 and x > -1
Step-by-step explanation:
Step 1: Subtract 2 from both sides.
Step 2: Solve absolute value.
- We know x - 1 < 2 and x - 1 > -2.
Condition 1:
Condition 2:
Therefore, the answer is x < 3 and x > -1.