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3 years ago

-8.2 +9.1 Yes I’m just making sure I got this question right but tell me what the answer is pls!

Mathematics

1 answer:

Nat2105 [25]3 years ago

3 0

Answer:

0.9 is your answer.

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If a bike is $125 how much will it be when its discounted by 20%

weeeeeb [17]

Answer:

160 pages.

Step-by-step explanation:

That is 125 - 0.20 * 125

= 125 - 25

= 160 pages.

6 0

4 years ago

Read 2 more answers

Find the missing length. The triangles are similar.

Marina CMI [18]

Answer:

RK= 13 SK= 12

Step-by-step explanation

First, we find the missing length of RK using the given information: 65-52=13

Then we divide 65 by 13 to get a scale factor: 65/13=5

(To check, we multipuly: 13*5=65)

We then apply the scale factor to MK to find SK: 60/5=12

(To check we multipuly: 5*12=60)

We now have our answers: RK:13, SK:12

4 0

3 years ago

which of the following are remote interior angles of 5? check all that apply. a 4 b 5 c 6 d 1 e 2 f 3

77julia77 [94]

From my research, the image supports the question. The exterior angle 5 can have up to 2 remote interior angles. Remote interior angles are the two angles inside the triangle that do not share a vertex with the external angle. From the choices, the two remote interior angles are 1 and 3. Among the choices, the correct answers are D and F.

5 0

4 years ago

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT

Nina [5.8K]

The answer is the 3rd option. The first change is a rotation then a reflection.

8 0

3 years ago

Read 2 more answers

A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5

Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3) = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

= 1/3 (3*(H/L)²*Q) / h² = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

8 0

3 years ago