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Mathematics

1 answer:

sveticcg [70]3 years ago

3 0

Answer: B is (6,7)

Step-by-step explanation:

Put the two points like an equation with point A on top and midpoint M on the bottom like this:

A (-4,8)

M (1,7.5)

Now, look at the difference between the x points of point A and midpoint M. The difference is +5. Do the same for the y points between point A and M. The difference is -0.5. From point M, add 5 to 1 (which is the x point of M) and subtract 0.5 from 7.5 (which is the y point of M). Now you have (6,7) which is point B. I hope this helped!! :)

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Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$