We have this equation:

First, combine both logarithms using the multiplication property and simplify the expression.
![\log[x(x + 99)] = 2](https://tex.z-dn.net/?f=%5Clog%5Bx%28x%20%2B%2099%29%5D%20%3D%202)
![\log[ {x}^{2} + 99x ] = 2](https://tex.z-dn.net/?f=%5Clog%5B%20%7Bx%7D%5E%7B2%7D%20%2B%2099x%20%5D%20%3D%202)
Now, use the definition of logarithm to transform the equation.


Finally, use the quadratic formula to solve the equation.

With this, we can say that the solution set is:
We cannot choose x = -100 as a solution because we cannot have a negative logarithm. The only solution is x = 1.
Answer:
A‘‘ (1,6)
Step-by-step explanation:
after a reflection about a horizontal line the x coordinates remain the same
the middle point of the segment AA’ lies on the line so it has y = -1
so we have
(y+y’)/2 = -1
y’ = -2 -y
y‘ = -2 -2 = -4
so A‘ (1,-4)
we can use the same reasoning to find the reflection about y = 1
x‘ = x
(y + y’)/2 = 1
y‘ = 2+4
y’ = 6
A‘‘(1,6)
Answer:
<h2><u>
A</u></h2>
Step-by-step explanation:
<h2>
You are going 2 up because it says plus 2 so A.</h2>