All categories

3 years ago

0.4 greater or less than 0.41

2 answers:

8 0

0.40 is less than 0.41

Unless it is a trick question and 0.4 was rounded down from a larger number then this should be the correct answer.

marshall27 [118]3 years ago

4 0

0.4 is exactly 0.01 less than 0.41 .

You might be interested in

Find the missing number in this proportion. 6 16 = 30 ?

Slav-nsk [51]

80 because of you cross multiply 6 times x and 30 times 16 you get 480 and 6 divided by 480 is 80

6/16=30/?
6x=480
Divided by 6
?=80

4 0

3 years ago

Which best describes your ability to use graphs to model relationships?

alekssr [168]

Answer:

My answer is C

Step-by-step explanation:

I know how to use a graph kind of but I have trouble of calculating and stuff like that.

3 0

2 years ago

A sphere and a right cylinder have the same radius and volume. The cylinder has a height of 8 feet. Find the radius.

siniylev [52]

9514 1404 393

Answer:

6 feet

Step-by-step explanation:

The volume of a cylinder is given by ...

V = πr^2·h

For a sphere, the volume is ...

V = 4/3πr^3

You want the volumes to be the same when h=8, so we have ...

πr^2·8 = 4/3πr^3

Dividing by πr^2, we have ...

8 = 4/3r

r = 3/4·8 = 6

The radius is 6 feet.

8 0

3 years ago

(HELP! PLEASE!!! 50 POINTS!! JUST TWO QUESTIONS) 1. Using the numbers 5, 8, and 24, create a problem using no more than four ope

andreev551 [17]

Answer:Davinki

Step-by-step explanation:made the mona lisa

4 0

3 years ago

A Norman window has the shape of a semicircle atop a rectangle so that the diameter of the semicircle is equal to the width of t

Makovka662 [10]

Answer:

132.233 ft2

Step-by-step explanation:

Let's call the width of the rectangle 'w' and the length 'x'. So the area of the semicircle is:

$A_1 = \pi*radius^2/2$

$A_1 = \pi*(w/2)^2/2$

$A_1 = \pi/8*w^2$

And the area of the rectangle is:

$A_2 = w*x$

If the perimeter of the window is 41 feet, we have:

$Perimeter = length + 2*width + \pi*radius$

$41 = x + 2*w + \pi*w/2$

$x = 41 - w(2 + \pi/2)$

Now, the equation for the total area of the window is:

$A = A_1 + A_2 = \pi/8*w^2 + w*x$

$A = \pi/8*w^2 + w*(41 - w(2 + \pi/2))$

$A = (\pi/8-2 - \pi/2)*w^2 + 41w = -3.1781w^2 + 41w$

To find the maximum area, we can find the x-coordinate of the vertex of the quadratic equation:

$x\_vertex = -b / 2a = -41 / (-3.1781*2) = 6.45$

So the width that gives us the maximum area of the window is 6.45 feet, and the area will be:

$A = -3.1781w^2 + 41w = -3.1781*(6.45)^2 + 41*6.45 = 132.233\ ft^2$

3 0

3 years ago