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makkiz [27]
3 years ago
7

What is the answer to 3x+3y=8 -2x+5y=9

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

Hey if u download photomath it helps alot with math problems

Step-by-step explanation:

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Find the Equation of the line
romanna [79]

Answer:

y = \frac{1}{2}x + \frac{1}{2}

Step-by-step explanation:

Mark any two point on the line

(-1 , 0)  & (-3 , -1)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\

          = \frac{-1-0}{-3-[-1]}\\\\= \frac{-1}{-3+1}\\\\= \frac{-1}{-2}\\\\= \frac{1}{2}

m = 1/2   ; (-1 , 0)

Equation: y - y_{1} =m(x -x_{1})

y - 0 = \frac{1}{2}(x - [-1])\\\\y = \frac{1}{2}(x + 1)\\\\y = \frac{1}{2}x + \frac{1}{2}

5 0
3 years ago
What is the percent change in the price of a gallon of gas, to the nearest whole percent?
Hatshy [7]

Answer: 3.499 now 3.079 is correct

8 0
3 years ago
Can you see farts<br><br><br><br> 2+2+2+2+2+2+2=?
mihalych1998 [28]
With a thermal camera, yes you can see farts, otherwise to the naked eye, it is impossible to see farts
8 0
4 years ago
Read 2 more answers
Point C is located at (1, 2), and point D is located at (-4,-2). Find the point that is the distance from point C
marishachu [46]

Answer:

The answer would be c

Step-by-step explanation:

i choosed c because u have da negative sign in front of 4 and 2 and positive numbers with 1 and 2

6 0
3 years ago
Read 2 more answers
Question 6
Firdavs [7]
So hmmmmm, notice... the boat went up in 3hrs, came back to the starting point in 2hrs, it went up 108km, it came back, well, from 108km to distance 0, so the distance on the way back is just the same 108km

now... let's say the stream has a speed rate of "r", and the boat has a still water speed rate of "b"

bear in mind that, when the boat is going UP, is not really going "b" fast, because the stream's "r" rate is going against it, and thus subtracting "r" from "b", so is really going " b - r " fast

when the boat is going down, is not going "b" fast either, because, again the stream's rate "r" is adding to it, because is going with the current, so is really going " b + r " fast

now, recall your d =rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;upstream&108&b-r&3\\&#10;downstream&108&b+r&2&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;108=3(b-r)\implies \frac{108}{3}=b-r\\&#10;\qquad 36=b-r\implies 36+r=\boxed{b}\\\\&#10;108=2(b+r)\implies 54=b+r\\&#10;\qquad 54=\boxed{36+r}+r&#10;\end{cases}

solve for "r"

what's b?  well, 36+ r = b
7 0
4 years ago
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