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3 years ago

HELP ME PLEASE !! Determine whether the relation is a function. Explain.

Mathematics

2 answers:

GarryVolchara [31]3 years ago

8 0

Answer: Yes, The relation is a function, they are the exact opposite.

Step-by-step explanation:

nevsk [136]3 years ago

7 0

It’s a function because every x value has only 1 y value.

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Just need the answers to see if im right lol

denis-greek [22]

Answer:

what is the question ? Volume or surface area???

6 0

3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago

Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please

Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1) 7x + 8y = 20

(2) 7x – 2y = 29 Subtract (2) from (1)

10y = -9 Divide each side by 10

(3) y = -⁹/₁₀ Substitute (3) into (1)

7x - 2(-⁹/₁₀) = 29

7x + 18/10 = 29 Subtract 18/10 from each side

7x = 29 - 18/10

7x = (290 - 18)/10

7x = 272/10 Divide each side by 7

x = 272/70

x = 136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

136/5 - 72/10 = 20

136/5 - 36/5 = 20

100/5 = 20

20 = 20

(2) 7(136/35) – 2(-⁹/₁₀) = 29

136/5 + 18/10 = 29

136/5 + ⁹/₅ = 29

145/5 = 29

29 = 29

5 0

3 years ago

Please help me out you guys

s344n2d4d5 [400]

Answer:

okok I willl hel0 you out

5 0

3 years ago

Read 2 more answers

Are a total of 127 Cars And trucks on a lot. If there. For more than twice the number of trucks, then cars, how many cars and tr

kow [346]

Answer:

41 cars and 86 trucks

Step-by-step explanation:

C+T=127

2C+4=T

C+(2C+4)=127

3C+4=127

3C=123

C=41When C=41,

41+T=127

T=127-41

T=86

3 0

3 years ago