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ch4aika [34]
3 years ago
7

Suppose the price of a certain item decreases by 5.2% a total of 5 times, and then increases by 1.4% a total of 3 times. By what

overall percent did the price decrease?
Round your answer to the nearest tenth of a percent.
Mathematics
1 answer:
Vanyuwa [196]3 years ago
3 0

Answer:

So percent decrement in price will be 20.17 %  

Step-by-step explanation:

Let the price of item is x

It is given that price is decreases 5.2 % five times and increases 1.4 % three times

So price of item after detriment of 5.2 % five times and increment of of 1.4 % three times = x(1-5.2%)^{5}\times (1-1.4%)^3

= x\times0.948^5\times 1.014^3

Decrements in price = x-x\times0.948^5\times 1.014^3

%v decrements = \frac{x-x\times0.948^5\times 1.014^3}{x}\times 100=20.17

So percent decrement in price will be 20.17 %

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If Sandy's cookie recipe calls for 1/3 cup of brown sugar and she increases it to 2/9, how much brown sugar does she use?
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svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
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