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WARRIOR [948]
3 years ago
14

The memory card on melcher did it's camera can hold about 430 pictures. Melcher used 18% of the memory card while taking picture

s at s family reunion about how many pictures did melcher take at the family reunion
Mathematics
2 answers:
NeX [460]3 years ago
8 0
The answer I got was about 77 photos but then if u have to estimate the it could be 80
Korolek [52]3 years ago
7 0
Just cross multiply to find 18% of 430
18/100 = x/430
430 X 18 = 7740
7740 = 100x
7740/100 = 77.4
so Melcher took about 77 photos.
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The length of an object's shadow varies directly with It's heigt. If a can is 13 cm tall casts a shadow that is 7.5 cm long, a b
svetoff [14.1K]
X = Can/Bottle height, y = Shadow length
x = 13 cm, y = 7.5 cm
x = 2.5 cm, y = 14.2 cm
I'm assuming your question is asking for an equation to model this. Since there are only two data points the only equation that can be made is linear
y = mx + c
m = (y2 - y1)/(x2 - x1) <- Let 14.2 be y2, and 2.5 be x2 (it is important)
m = (14.2 - 7.5)/(2.5 - 13)
m = 6.7/-10.5
m = -0.638
y = -0.638x + c
To find c we can sub any one of the two coordinates, 
i'm choosing (2.5,14.2)
14.2 = -0.638(2.5) + c
14.2 = -1.595 + c
14.2 + 1.595 = c
15.795 = c
So the final equation is y = -0.638x + 15.795
6 0
3 years ago
Car dealerships claim to make most of their money from servicing cars. In a certain month, an Acura dealership sold fifteen less
MA_775_DIABLO [31]

Answer:

New cars sold = 20,

Used cars sold = 25

Cars serviced = 290

Step-by-step explanation:

In a month they sold fifteen less used cars than twice the number of new cars.

Lets say 'x' number of new cars were sold, then:

The number of used car sold is:

2\times x-15=2x-15

In the same month they serviced fifty more than twelve times the number of new cars sold. So the number of cars serviced is:

12\times x+50=12x+50

Altogether they sold or serviced 335 cars, so the sum of all the cars sold and serviced should be 335:

x+(2x-15)+(12x+15)=335

Solving for 'x' we get:

x+2x+12x-15+50=335

15x+35=335

15x=335-35=300

x=\frac{300}{15}=20

Therefore, the number of new cars sold in that month is 20.

Number of used car sold =2x-15=2\times 20-15=40-15=25

Number of cars serviced =12\times x+50=12\times20+50=240+50=290

We can also cross check by summing them up:

290+25+20=335

8 0
3 years ago
Solve this equation 52! / (52-5)!5!
dangina [55]

Answer:

C= 2,598,960

Step-by-step explanation:

let me know if you want a step by step explanation!

6 0
2 years ago
Read 2 more answers
18. A soccer ball is kicked upward from a height of 1.5 feet with an initial vertical velocity of 35 feet per second. Its
NemiM [27]

Answer:

Part a) -16t^{2}+35t+1.5=0

Part b)

a=-16\\b=35\\c=1.5

Part c) The soccer ball will take 2.23 seconds to reach the ground

Step-by-step explanation:

we have

h(t)=-16t^{2}+35t+1.5

where

t  is the time the ball has been in the air, in seconds

h(t) is the height, in feet, of the  soccer ball

Part a) Write an equation that could be used to determine the time the ball traveled before it hit the ground

we know that

When the ball hit the ground, the value of h(t) is equal to zero

so

For h(t)=0

-16t^{2}+35t+1.5=0

This equation can be used to determine the time the ball traveled before it hit the ground

Part b) Determine the values of a, b, and c

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+35t+1.5=0

so

a=-16\\b=35\\c=1.5

Part c)  How long will it take for the soccer ball to reach the ground after it was kicked?

Solve the quadratic equation by the formula

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

we have

a=-16\\b=35\\c=1.5

substitute the values

x=\frac{-35(+/-)\sqrt{35^{2}-4(-16)(1.5)}} {2(-16)}

x=\frac{-35(+/-)\sqrt{1,321}} {-32}

x_1=\frac{-35(+)\sqrt{1,321}} {-32}=-0.04  ---> cannot be a solution (is negative)

x_2=\frac{-35(-)\sqrt{1,321}} {-32}=2.23

therefore

The soccer ball will take 2.23 seconds to reach the ground

4 0
3 years ago
(−4 + 5) − (6 + 7) = x x 0
weeeeeb [17]

1

Add the numbers

(

−

4

+

5

)

−

(

6

+

7

)

=

0

({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}

(−4+5)−(6+7)=xx0

(

1

)

−

(

6

+

7

)

=

0

({\color{#c92786}{1}})-(6+7)=xx^{0}

(1)−(6+7)=xx0

2

Add the numbers

1

−

(

6

+

7

)

=

0

1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

1−(6+7)=xx0

1

−

(

1

3

)

=

0

1-({\color{#c92786}{13}})=xx^{0}

1−(13)=xx0

3

Multiply the numbers

1

−

1

⋅

1

3

=

0

1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

−

1

3

=

0

1{\color{#c92786}{-13}}=xx^{0}

1−13=xx0

4

Subtract the numbers

1

−

1

3

=

0

{\color{#c92786}{1-13}}=xx^{0}

1−13=xx0

−

1

2

=

0

{\color{#c92786}{-12}}=xx^{0}

−12=xx0

5

Combine exponents

−

1

2

=

0

-12={\color{#c92786}{xx^{0}}}

−12=xx0

−

1

2

=

1

-12={\color{#c92786}{x^{1}}}

−12=x1

Show less

Solution

−

1

2

=

1

3 0
3 years ago
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