Let's say imput is i and that output is o.
The formula is 2 ^ i = o
2^0 = 1
2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
Notice how the numbers match?
Hope this helped :)
It would be B (530.7) because if you do 3.14 x 13 x 13 (Or to the second power) Then you get 530.66, the round to the nearest tenths
Answer:
Step-by-step explanation:
Y = mx + b
slope(m) = 3/4
(3,7)...x = 3 and y = 7
now we sub...we r looking for b, the y int
7 = 3/4(3) + b
7 = 9/4 + b
7 - 9/4 = b
28/4 - 9/4 = b
19/4 = b
equation is : y = 3/4x + 19/4...lets put this in standard form
y = 3/4x + 19/4
-3/4x + y = 19/4...multiply by -4
3x - 4y = -19 <== standard form
if (x,5) is on the line
3x - 4y = -19.....sub in 5 for y
3x - 4(5) = -19
3x - 20 = -19
3x = -19 + 20
3x = 1
x = 1/3 <====so point a = (1/3,5)
9514 1404 393
Answer:
48
Step-by-step explanation:
Let d represent the number of sweets Dora has to start with. Then 2d is the number Harini had. After they each ate 18, the ratio of their numbers is ...
(2d -18)/(d -18) = 5/1
2d -18 = 5(d -18) . . . . . multiply by d-18
72 = 3d . . . . . . . . . . subtract 2d-90
24 = d . . . . . . . . . divide by 3
2d = 48
Harini started with 48 sweets.
P(6) = 1/6
P(4 or 5) = 2/6
P(1, 2 or 3) = 3/6
P(gold or silver or bronze) = 1/6 + 2/6 + 3/6 = 1
