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Sonbull [250]
3 years ago
7

Evaluate: 8^8/3= ???

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0
(5.59241)(10)^6 *Possible Answer*
-BARSIC- [3]3 years ago
4 0

The correct answer to those who may still need it is:

8^8/3= 256

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Find the fair share. ⅜, ⅙, ⅙, ⅛, ½, ¼, ½, ⅔, ¼, ¾, ⅜, ¼, ⅜, ¼
Vlada [557]
2/3rds is the answer. Good luck
5 0
2 years ago
△ABC @ △DEF. Find the measures of the given angles or the lengths of the given sides
brilliants [131]

Answer:

BC = EF = 8

Step-by-step explanation:

Assuming you mean BC ≅ EF, then ...

... 3z +2 = z +6

... 2z = 4 . . . . . . . . add -2-z

... z = 2 . . . . . . . . . divide by 2

BC = EF = 2+6 = 8

7 0
3 years ago
13 less than 8 times a number is the same as the number plus 1
aliya0001 [1]
8x - 13 = x + 1
Solve for x
Add 13
8x = x + 14
Subtract x
7x = 14, x = 2
Answer: the number is 2
7 0
3 years ago
Louis wants to carpet the rectangular floor of his basement. The basement has an area of 500 square feet. The width of the basem
Mazyrski [523]

Answer:

The correct answer is the length is 10 feet and width is 2 feet respectively.

Step-by-step explanation:

Let length of the rectangular floor of Louis' basement be l feet and width be \frac{l}{5} feet respectively.

Area of the basement floor is given to be 500 square feet.

Therefore according to the given problem,

l × \frac{l}{5}  = 500

⇒ l^{2} = 100

⇒ l = 10 ; [length cannot be negative]

⇒ b = 2

Thus the length and width be 10 feet and 2 feet respectively.

4 0
3 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

Highway = 155\ miles

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
3 years ago
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