For the mix you need 60 Ib of nuts and raisins, and 60 lb of mix will sell for $300.
Let <em>x</em> be the weight of nuts and <em>y</em> the weight of raisins needed for the mix.
Total weight = <em>x</em>+<em>y</em> = 60, so <em>y</em> = 60 - <em>x</em>
Total value = 6<em>x</em> + 3<em>y</em> = 300. From the above, we can substitute the <em>y</em> for 60 - x:
Total value = 6<em>x</em> + 3(60 - <em>x</em>) = 300, which we can simplify to:
6<em>x</em> + 180 - 3<em>x</em> = 300, and simplify again to:
3<em>x</em> = 120, and again to:
<em>x</em> = 40. We can now calculate<em> y</em> from the first equation y = 60 - <em>x</em>, so:
y = 20.
40 lb of nuts and 20 lb of raisins. Check:
40 lb x $6/lb = $240, and 20 lb x $3/lb = $60, $240 + $60 = $300.
The answer for the problems are below in the picture let me know if that makes sense.
Answer:
-1
Step-by-step explanation:
Tip: Remember to always start from the inside, which would be g(3), in this case.
The first step in solving this problem is to solve for g(3).
To accomplish this, you must substitute 3 for x into the given equation g(x) = x^2 - 10
- g(3) = 3^2 - 10
- g(3) = 9 - 10
- g(3) = -1
The next step is to substitute the answer of g(3), -1, for x in the given equation f(x) = 2x + 1.
Because the equation is asking for f[g(3)], it becomes f(-1) because g(3) = -1.
- f(-1) = 2(-1) + 1
- f(-1) = -2 + 1
- f(-1) = -1
Therefore, f[g(3)], or f(-1), equals -1
Answer:
1/3?
Step-by-step explanation:
Answer:
June has 40 Sweets
Step-by-step explanation:
The computation of the sweets does June have is as follows:
Let us assume June have x sweets
As per the question
May has 3x ÷ 4 sweets
April has (3x ÷ 4 × 2 ÷ 3) = x ÷ 2 sweets
And, the total sweets is 90
Now
x ÷ 2 + 3x ÷ 4 + x = 90
9x = 360
x = 40
Therefore June has 40 Sweets
