I know that you should use PEMDAS, what grade are you in this sems advances for you
Assuming that all the grapes have the same probability of being randomly picked:
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How to find the probabilities?</h3>
We know that there are 8 green grapes and 15 red grapes on the bowl, so there is a total of 23 grapes.
a) Here we need to find the probability that both grapes are green. Remember that the probability of getting a green grape is equal to the quotient between the number of green grapes and the total number of grapes, this is:
P = 8/23
But then he must take another, because he already took one, the number of green grapes is 7, and the total number of grapes is 22, so for the second grape the probability is:
P' = 7/22.
The joint probability is the product of the two individual probabilities:
prob = (8/23)*(7/22) = 0.11
b) For the first green grape we know that the probability is:
P = 8/23
Then he must get a red grape. There are 15 red grapes and 22 grapes in total, so the probability is:
P' = 15/22
Then the joint probability is:
prob = (8/23)*(15/22) = 0.24
If you want to learn more about probability:
brainly.com/question/25870256
#SPJ1
X=1/6 or 4/24 but go with the first one because its simplified
Copper and silver <span>tarnish quickly in air</span>
Answer:
ok here's what i think:
first box is 30
second box is between 20 and 70
third box is more than 70
I'm not absolutley sure and I may be wrong
