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To find the lateral surface area of a pyramid, you can find the area of each triangle, A = 1/2bh or A = 1/2lw, then multiply by the number of triangles, which would be based on the number of sides of the base; or you can take half the perimeter and multiply by the slant height.
Answer:
It’s 10n+12
They put the 2 n’s as an exponent
Step-by-step explanation:
Just use your right angled triangle formula.
A=

Plug n chug
A=

A=71.5
Hello!
<h2>
31.3° and 58.7°</h2><h2>
</h2>
To solve, we can set up an algebraic expression.
Complementary angles add up to 90°, and in this instance, one angle is 27.4° more than the other. Therefore:
∠1 = x
∠2 = x + 27.4°
∠1 + ∠2 = 90°
x + (x + 27.4°) = 90°
Combine like terms:
2x + 27.4° = 90°
Subtract 27.4 from both sides:
2x = 62.6°
Divide both sides by 2:
x = 31.3°
Therefore, one of the angles is 31.3°. Solve for the measure of the other angle:
(31.3°) + 27.4° = 58.7°