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Vlada [557]
3 years ago
9

Please help me with this ​

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

7. 5 \frac{5}{8} pizza

8. B

9. 11 \frac{1}{5} inches

10. -12

11. \frac{3}{20}

12. 4

Step-by-step explanation:

7. 3 \frac{1}{2} \\ + 2 \frac{1}{8}

make them mixed fractions: \frac{7}{2} + \frac{17}{8}

get a common denominator by multiplying \frac{7}{2} by 4: \frac{28}{8} + \frac{17}{8}

add the numerators: \frac{45}{8}

simplify the fraction by dividing 45 by 8: 5 \frac{5}{8}

8. 3 x 6 = 18

5 x 6 = 30

7 x 6 = 42

9 x 6 = 54

therefore, y = 6x

9. 5:7 is similar to 8:L

divide 8 by 5: 1 \frac{3}{5}

multiply 7 by 1 \frac{3}{5}: 11 \frac{1}{5}

L = 11 \frac{1}{5} inches

10. 5 - 2x = 29

subtract 5 from each side: -2x = 24

divide each side by -2: x = -12

11. fruit = 15%

15% = 15/100

simplify by dividing by 5: \frac{3}{20}

12. the y-intercept is where the line crosses the y-axis (the vertical one). the line crosses the y-axis at 4.

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65 % of 60 is what number?
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39

Step-by-step explanation:

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B. The school prom committee sold presale tickets for
Ivan

Answer:

218 students purchased tickets at the dance.

Step-by-step explanation:

Let,

x be the number of presale tickets

y be the number of tickets sold at the dance

According to given statement;

x+y=334      Eqn 1

18x+24y=7320    Eqn 2

Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012      Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

18x+24y-18x-18y=1308

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\frac{6y}{6}=\frac{1308}{6}\\y=218

Therefore,

218 students purchased tickets at the dance.

5 0
3 years ago
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gregori [183]

Answer:

B. (8, 4)

Step-by-step explanation:

Hope this helps!

3 0
2 years ago
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Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
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