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Artemon [7]
3 years ago
14

Y

- 2 " alt="y = (x + 1)^{2} - 2 " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
lara31 [8.8K]3 years ago
4 0
Next time, please include the instructions.

I can only guess what you're trying to do here. 

suppose you started out with y = x^2.  If you were to graph this, and then you were to move the graph 1 unit to the left and 2 units down, you'd have the graph of   y = (x+1)^2 - 2.
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$10.50 an hour

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kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
3 years ago
Need help with this math lesson
never [62]

Answer: 50.24

3.14 x 4²

3.14 x 16

50.24

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