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3 years ago

7. 6h - 18 < 6h + 1

Mathematics

1 answer:

rosijanka [135]3 years ago

4 0

Answer:

<h2>Explanation:</h2>

In this exercise we have to solve the following inequality:

$6h-18$

Step 1. Subtract 6h from both sides:

$6h-18-6h$

Step 2. Simplify:

$6h-6h-18$

This is always true because -18 is a number less than 1. Therefore, for any real h-value the inequality is always true.

<h2>Learn more:</h2>

Inequality: brainly.com/question/12890742

#LearnWithBrainly

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A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. inside the container there is empty space not

asambeis [7]

Volume of Sphere is V=(4/3)*PI*r^3

The radius of the volleyball is 13 inches

<span>So V=(4/3) * 3.14 * 13^3 = 9198 cubic inches</span>

Volume of a cylinder is V=pi * r^2 *h

Since they say the ball fits perfectly

The radius is 13 and the height is 26 ( the diameter of the ball)

So V=3.14 * 13^2 * 26 = 13,797 cubic inches

13797 – 9198 = 4,599 cubic inches of empty space

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3 years ago

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Find the area of the triangle.

Thepotemich [5.8K]

Answer:

$270 \:m^2$

Step-by-step explanation:

The area of the triangle.

$bh\frac{1}{2}$

$b \times h \times \frac{1}{2}$

$20 \times 27 \times \frac{1}{2}$

$540 \times 1/2$

$=270$

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4 years ago

HELP WITH THIS QUESTION PLEASE!

belka [17]

Answer:

23.7°

9.1~ft

Step-by-step explanation:

Formula for the area of a sector of central angle n (in degrees) and radius r:

$A = \dfrac{n}{360^\circ}\pi r^2$

We have:

A = 100 ft^2

r = 22 ft

We need to find:

$100 = \dfrac{n}{360^\circ}\pi (22^2)$

$n = 23.7^\circ$

The central angle measures 23.7°.

Formula for the length of an arcs of a circle with central angle n (in degrees) and radius r:

$s = \dfrac{n}{360^\circ}2 \pi r$

We have:

n = 23.7°

r = 22 ft

We need to find:

$s = \dfrac{74.4}{360}2 \pi (22 ft)$

$s = 9.1~ft$

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3 years ago

Distance between parallel lines y=3x+10 and y=3x-20

Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).

2. Use formula $d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}$ to find the distance from point $(x_0,y_0)$ to the line Ax+By+C=0.

The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

$d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}$ .

3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.

Answer: $d=3\sqrt{10}$ .

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3 years ago

HELP 20 POINTS!

Butoxors [25]

For the first blank where it asks for the perimeter, the perimeter is all the outside sides of a shape added up. So, 6 + 1 + 2 + 4 + 4 + 5 = 22.

For the second blank, you just multiply the entire perimeter by 5, so, 22 times 5=110.

For the third blank, it is basically the same as the previous question. The answer is 5.

For the fourth blank, it is the same perimeter as the first blank, but instead of centimeters, it is in k. So, 22k.

Hope this helped! :)

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3 years ago

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7. 6h - 18 < 6h + 1​

7. 6h - 18 < 6h + 1