There are linear relationships so long as the power of x is 1 when power of y is 1 / power of x is not 2 and above when power of y is 1. This is assuming you plot the vertical axis as y-axis and the horizontal axis as the x-axis.
So using this concept, the equation with linear relationships are:
1, 3, 4, and 5.
Hope this helps! :)
So the area of a rectangle is Length x Width.
A = (L)(W)
Substitute the information given:
4x^2 + 20x + 16 = (L)(2x+8)
Isolate L by dividing 2x+8:
(4x^2 + 20x +16)/ (2x + 8) = L
If you divide:
L = 2x + 2.
Tenths: 10%, 20%, 30%, 40%, 50%, 60%, 70%, 80%, 90%, 100%
fifths: 20%, 40%, 60%, 80%,100%
fourths: 25%, 50%, 75%, 100%
P.S. I'm doing this like:
tenths: something/10
fifths: something/5
fourths: something/4
Answer:
19/6 u^3 v + v^2
Step-by-step explanation:
3uv2
u2−2v2+
5uv3
u2+3v2
=32
u3v+−2v2+53
u3v+3v2
Combine Like Terms:
=32
u3v+−2v2+53
u3v+3v2
= (3
u3v+
53
u3v)+(−2v2+3v2)
