<span>[square root (8x^9y^4)]²=</span><span>8x^9y^4
</span>[3x^4y^2 square root (2x)]²=9x^8y^4 .2x=18<span>x^9y^4
the answer is
</span>square root (18x^9y^4=
<span>B. 3x^4y^2 square root (2x)
</span>
square root (2)- square root (10)/ square root (2)+square root (10)
(√2-√10) /√2+√10=(√2-√10) (√2-√10)/(√2+√10)(√2-√10 )=(√2-√10)²/2-10
2+10-2√5/-8=(√5-6)/4, it is the same of
<span>A. -3/2+1/4 square root (10)
</span>
27^2/3 =∛27²=∛3^3)^2=∛3^3x2=<span>∛3^2)^3=3^2=9
</span>
the answer is
<span>C. 9</span>
Answer:
(0, ±2√5)
Step-by-step explanation:
The foci are the points on the major axis that are the length of the semimajor axis away from the co-vertices.
Here, that means their y-coordinate is ±√(36-16) = ±√20 = ±2√5.
The x-coordinate is that of the major axis, x=0.
Answer:
i dont know
Step-by-step explanation:
Answer:
-12
Step-by-step explanation:
Just multiply 6 times -2 to get the answer
Answer:x = 56
Step-by-step explanation:
180-(60+64)=56