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2 years ago

Can someone help me on question 7b ?

Mathematics

1 answer:

Marizza181 [45]2 years ago

4 0

Lengths are given to 1dp so the biggest that the lengths could be is 4.65cm and 5.35cm. if you use pythagoras on these to find hypotenuse, this is the upper bound.

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Milena's take-home pay is $1200 a month. She spends 12% of her take-home pay on her cable bill. How much is Milena's monthly cab

Dahasolnce [82]

Hi there! The cable bill is a portion of Milena's take-home pay. To find out how much her cable bill costs, all you have to do is multiply 1,200 by 12%. We multiply price and percentage together for problems like these. 1,200 * 12% (0.12) is 144. There. Milena's monthly cable bill is $144.

5 0

3 years ago

Read 2 more answers

Help me please by solving and showing the steps:)

Lorico [155]

Answer:

$-\frac{3\sqrt[3]{t} }{2}$

Step-by-step explanation:

1: Write g(t) as y, resulting in $y=-\frac{8}{27}t^3$

2: Interchange the variables y and t, resulting in $t=-\frac{8}{27}y^3$

3: Multiply both sides by 27, resulting in $27t=-8y^3$

4: Divide both sides by -8, resulting in $-\frac{27t}{8}=y^3$

5: Find the cube root of both sides, resulting in $\sqrt[3]{-\frac{27t}{8} }=y$

6: Apply a radical rule, resulting in $-\sqrt[3]{\frac{27t}{8} } =y$

7: Apply another radical rule, resulting in $-\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y$

8: Simplify the denominator, resulting in $-\frac{\sqrt[3]{27t} }{2} =y$

9: Apply yet another radical rule, resulting in $-\frac{\sqrt[3]{27}\sqrt[3]{t} }{2} =y$

10: Simplify $\sqrt[3]{27}$ , resulting in $-\frac{3\sqrt[3]{t} }{2} =y$

3 0

2 years ago

A Rasmussen Reports survey of 1,000 US adults found that 42% believe raising the minimum wage will help the economy. Construct a

vitfil [10]

Answer:

(0.3798, 0.4602)

Step-by-step explanation:

Let p be the true proportion of US adults who believe raising the minimum wage will help the economy. A point estimate for p is $\hat{p}=0.42$ and a good aproximation (because we have a large sample) for the standard deviation of $\hat{p}$ is $\sqrt{\hat{p}(1-\hat{p})/n}=\sqrt{0.42(0.58)/1000}=0.0156$ . Therefore, a 99% confidence interval for p is given by $\hat{p}\pm z_{\alpha/2}\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$ where $\alpha=0.01$ and $z_{\alpha/2}$ is the $\alpha/2$ th quantile of the standard normal distribution, so we have, $0.42\pm z_{0.005}0.0156$ , i.e., $0.42\pm(-2.5758)(0.0156)$ or equivalently (0.3798, 0.4602).

6 0

2 years ago

NEED MATH HELP QUICK!!! PlZ HELP!!!

ad-work [718]

Cy + b ÷a
Hope this helps :)

8 0

3 years ago

I need help can anyone help me

labwork [276]

In 7 years, the car was 18,000 and after 5 years it is worth 10,500 so if you subtract 18000-10500=7500 and if you do 7500/5=1500 so this means that the car was going down 1500 in value every year.

5 0

2 years ago