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lana [24]
3 years ago
6

Find the equation of the circle whose center and radius are given.

Mathematics
2 answers:
sveta [45]3 years ago
8 0

Answer:  The required equation of the circle is x^2+y^2-14x+6y+9=0.

Step-by-step explanation:  We are given to find the equation of the circle with center at the point (7, -3) and radius of length 7 units.

We know that

the standard equation of a circle with center at the point (h, k) and radius of length r units is given by

(x-h)^2+(y-k)^2=r^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

For the given circle,

center, (h, k) = (7, -3)  and  radius, r = 7 units.

From equation (i), we get

(x-7)^2+(y-(-3))^2=7^2\\\\\Rightarrow (x-7)^2+(y+3)^2=49\\\\\Rightarrow x^2-14x+49+y^2+6y+9=49\\\\\Rightarrow x^2+y^2-14x+6y+9=0.

Thus, the required equation of the circle is x^2+y^2-14x+6y+9=0.

trapecia [35]3 years ago
6 0
(x – h)² + (y – k)²<span> = r</span>² 

Fill in the numbers 

(x – 7)²<span> + (y +3)</span>²<span> = 49</span>
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